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https://hoursfinder.com/a-hours/a-man-with-a-paint-can-hours.html
The first painter can paint a house in 3 hours, so he can paint 1/3 of a house per hour. The second painter can paint a house in 5 hours, so he can paint 1/5 of a house per hour. We need to add their rates together: 1/3 + 1/5 To do this, we need to find a common denominator (3 x 5 = 15)
https://4wall-painting.blogspot.com/2010/02/man-can-pant-wall-in-one-hour-another.html
1hour=60 minutes 1and 1/2 hour=90minutes. We can now reword this to say: A man can paint the wall in 1/60 of an hour, and another man can paint the same wall in 1/90 of an hour. together they complete 1/60+1/90=1/36 of the wall in an hour. The time it will take them to complete the wall is simply the reciprocal of the value.
https://www.braingle.com/brainteasers/1957/painting-a-room.html
Answer. 80 minutes. Man A can paint a room in 2 h: 1 room/2 hours. Man B can paint a room in 4 h: 1 room/4 hours. Add the times together with the lowest common denominator of 4: 2/4 + 1/4 = 3 rooms/4 hours. We know how long it takes to do three rooms, but we want to know how long it would take to paint one:
https://brainly.com/question/11712594
Let the number of houses paint by 18 men in 6 hours be x. One man can paint one house in 12 hours. The part of house painted by a man in 1 hour is . The part of house painted by a man in 6 hour is. The total number of men is 18. Therefore the number of houses painted by 18 men is. Therefore correct option is C. 9 houses could 18 men paint in 6 hours.
https://mathquestions.quora.com/If-man-can-paint-one-door-in-1-1-4-hours-how-many-doors-can-he-paint-in-7-1-2-hours
Work problems like this always depend on the constant product of number of workers and the elapsed time. The product is constant because the amount of work is constant. The formula is 5 men * 3 hours = x men * 3/4 hours. Solving for x. 5 men * 3 hours = x men * 3/4 hours. 15 men-hrs = x men-hrs. x men-hrs = 15 men-hrs * 4/3 * 1/hr. x = (60 / 3) men. x = 20 men
https://education.blurtit.com/192304/if-a-one-man-can-paint-a-house-in-5-hours-and-another-can-paint-it-in-3-how-long-would-it
Answer (1 of 6): 1 hour = 1/5 of the house1 hour = 1/3 of the house. Both together, 1/3+1/5 = 8/15 of the house in 1 hour. 1/15 of the house in 1/8 hours15/15 of the house in 1/8 x 15 = 15/8 hours= 1.875 hours. They both can paint the house in 1.875 hours.
https://opentextbc.ca/intermediatealgebraberg/chapter/9-10-rate-word-problems-work-and-time/
Tim can finish a certain job in 10 hours. It takes his wife JoAnn only 8 hours to do the same job. If they work together, how long will it take them to complete the job? Two people working together can complete a job in 6 hours. If one of them works twice as fast as the other, how long would it take the slower person, working alone, to do the job?
https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.22995.html
If Sally can paint the house in 4 hours, then in 1 hour she can paint 1/4 of the house. If John can paint the house in 6 hours, then in 1 hour he can paint 1/6 of the house. Let x = number of hours it would take them together to paint the house, then working together, in 1 hour they can paint 1/x of the house. The equation is this:
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