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https://linuxconfig.org/addition-and-subtraction-arithmetics-with-linux-date-command#:~:text=Subtract%20hours%20and%20minutes%20from%20the%20current%20date%3A,%2B%25H%25M-%25d%25m%25Y%20Tue%20Jul%2013%2021%3A16%3A45%20EDT%202021%202111-13072021
https://stackoverflow.com/questions/5934394/subtract-1-hour-from-date-in-unix-shell-script
Here another way to subtract 1 hour. yesterdayDate=`date -d '2018-11-24 00:09 -1 hour' +'%Y-%m-%d %H:%M'` echo $yesterdayDate Output: 2018-11-23 23:09 I hope that it can help someone.
https://unix.stackexchange.com/questions/497639/subtract-time-using-date-and-bash
date -d "2018-12-10 00:00:00 - 5 hours - 20 minutes - 5 seconds". This results in 2018-12-10 06:39:55 - It added 7 hours. Then subtracted 20:05 minutes. After reading the man and info page of date, I thought I have it fixed with this: date -d "2018-12-10T00:00:00 - 5 hours - 20 minutes - 5 seconds". But, same result.
https://unix.stackexchange.com/questions/93656/subtracting-dates-in-unix
DAY30=`TZ=EST+720 date "+%Y-%m-%d"` print $DAY30 720 is the offset in hours. So, 30 days is 720 hours. EST is my time zone. I assume that you can use whatever time zone is appropriate.
https://unix.stackexchange.com/questions/490764/subtract-time-using-bash
The date command is pretty flexible about its input. You can use that to your advantage: #!/bin/bash var1="23:30" var2="20:00" # Convert to epoch time and calculate difference. difference=$(( $(date -d "$var1" "+%s") - $(date -d "$var2" "+%s") )) # Divide the difference by 3600 to calculate hours. echo "scale=2 ; $difference/3600" | bc Output:
https://linuxconfig.org/addition-and-subtraction-arithmetics-with-linux-date-command
Subtract hours and minutes from the current date: $ date; date --date="5 hours ago" +%H%M-%d%m%Y Tue Jul 13 21:16:01 EDT 2021 1616-13072021 As you can probably guess, we follow the same format to subtract minutes from current date: $ date; date --date="5 minutes ago" +%H%M-%d%m%Y Tue Jul 13 21:16:45 EDT 2021 2111-13072021
https://www.unix.com/unix-for-dummies-questions-and-answers/899-how-subtract-2-hours-date-shell-bin-sh-script.html
How to subtract 2 hours from 'date' in shell ( /bin/sh ) script ? I write a sh script that zip and copy to tape all files that older then 2 hours. 1. The way I choose is - touch a file with "now - 2 hours", then use fine with '! -newer'. 2.
https://unix.stackexchange.com/questions/24626/quickly-calculate-date-differences
I usually prefer having the time/date in unix utime format (number of seconds since the epoch, when the seventies begun, UTC). ... you could do it with multiple invocations of date. First subtract the days, then the months, then the years. ... yields 8.4591667 hours or, …
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