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https://stackoverflow.com/questions/30772434/how-to-subtract-hours-from-a-date-in-oracle-so-it-affects-the-day-also
sysdate-(2/11) A day consists of 24 hours. So, to subtract 2 hours from a day you need to divide it by 24: DATE_value - 2/24 Using interval for the same: DATE_value - interval '2' hour
https://community.oracle.com/tech/developers/discussion/26777/how-to-subtract-time-from-sysdate
select to_char(sysdate -8/24, ' dd-mm-yy hh24:mi:ss' ) "SUB_TIME" from dual ; Explanation : -----U can check out in this way sql> set time on 22:48:31 sql > now , if u want to remove 8 hours from sysdate, type the above statement as 22:48:35 sql> select to_char(sysdate -8/24 , ' dd-mm-yy hh24:mi:ss' ) "TIME " from dual ; displays as, TIME -----
https://community.oracle.com/tech/developers/discussion/899728/subtract-1-hour-from-date
SYSDATE - 1/24 or SYSDATE - INTERVAL '1' HOUR will subtract 1 hour from SYSDATE. In Oracle, when you add or subtract a number to a date, the unit is days. So SYSDATE + 1 adds 1 day. To add some other increment, you just multiply or divide appropriately, i.e. SYSDATE - 1/24 subtracts an hour, SYSDATE - 1/24/60 subtracts a minute, etc.
https://stackoverflow.com/questions/43193980/rounding-oracle-sysdate-to-the-nearest-hour
SYSDATE rounded to nearest passed hour (in this case 03.00.00) b. a minus 1 hour = 02.00.00 You can use TRUNC ( date_value, format_mask ) and subtract an INTERVAL literal: SELECT * FROM your_table WHERE date_column BETWEEN TRUNC ( SYSDATE, 'hh24' ) - INTERVAL '1' HOUR AND TRUNC ( SYSDATE, 'hh24' ); Share Improve this answer
https://p2p.wrox.com/oracle/8930-how-subtract-hours-sysdate-oracle.html
Hi mcmouli, You need to compare the date with (sysdate - 50/24) i.e. you need to convert 50 hours into days first. The following execution sequence shows how you can use "decode(sign())" function to compare the dates in the dummy table t.
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