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https://community.spiceworks.com/topic/2147958-substract-four-hours-from-current-date-time-and-get-date#:~:text=For%20example%2C%20if%20your%20date%2Ftime%20is%207%2F13%2F2018%2002%3A00,DATEADD%2C%20and%20just%20specify%20your%20hours%20%28see%20https%3A%2F%2Fdocs.microsoft.com%2Fen-us%2Fsql%2Ft-sql%2Ffunctions%2Fdate-and-time-data-types-and-functions-transact...%29
https://stackoverflow.com/questions/12756769/sql-convert-datetime-and-subtract-hours
declare @createTime datetime = '2012-10-06 02:29:37.243'; -- original value, default formatting select @createTime; -- formatted select convert(varchar, @createTime, 100); -- subtract 4 hours, formatted select convert(varchar, dateadd(hour, -4, @createTime), 100); The query above that uses dateadd will always subtract 4 hours. If your goal is to convert an arbitrary datetime from UTC to local …
https://www.raiseupwa.com/lifehacks/how-do-i-subtract-hours-and-minutes-in-sql/
https://ycsoftware.net/add-and-subtract-hours-to-t-sql-datetime/
Add to 1 hour to the Current Date. DATEADD(hh,1,getdate()) Subtract 1 hour to the Current Date. DATEADD(hh,-1,getdate()) Add 1 hour to the Current Time and returns just the time part. select Convert(varchar,( DATEADD(hh,-1,getdate())),8) Reference http://msdn.microsoft.com/en-us/library/ms186819.aspx
https://www.tutorialsrack.com/articles/393/how-to-add-and-subtract-dates-from-datetime-using-dateadd-function-in-sql-server
How to add or subtract hours, minutes or seconds, milliseconds, microseconds, nanoseconds to a specified Date in SQL Server? DATEADD() Function This function is simply used to add or subtract a specified number of units of DateTime to a specified DateTime such as year, months, days, hours, minutes, seconds, etc.
https://social.msdn.microsoft.com/Forums/en-US/97eb2336-8f1f-4749-a8e1-a80e2de1eefc/how-to-subtract-time-from-time-in-sql
User1912965948 posted Hi all, I want to get a total working hour per day, SQL Table Emp_Name Emp_No Date ClockIn ClockOut Tom Hardy 1 2018-10-01 2018-10-01 08:41:20 2018-10-01 18:56:19 Tom Hardy 1 2018-10-02 2018-10-02 08:38:40 2018-10-02 21:34:23 T · User-821857111 posted SELECT FORMAT(DATEADD(ss,DATEDIFF(ss,[ClockIn], [ClockOut] ),0),'hh:mm ...
https://stackoverflow.com/questions/23521088/how-do-i-subtract-two-date-columns-and-two-time-columns-in-sql
Once you've done that you can get the Days, Hours and Minutes like this: select DATEDIFF(minute, StartDate + StartTime, EndDate + EndTime) / (24*60) 'Days', (DATEDIFF(minute, StartDate + StartTime, EndDate + EndTime) / 60) % 24 'Hours', DATEDIFF(minute, StartDate + StartTime, EndDate + EndTime) % 60 'Minutess' from YourTable
https://community.spiceworks.com/topic/2147958-substract-four-hours-from-current-date-time-and-get-date
Date/Time fields are nothing more than a floating point number where the days are the integer part and the time is the decimal part. For example, if your date/time is 7/13/2018 02:00 then subtracting 4/24 would result in 7/12/2018 22:00 (four hours earlier). You can use the DATEADD, and just specify your hours (see https://docs.microsoft.com/en-us/sql/t-sql/functions/date-and-time-data-types …
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