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https://docs.microsoft.com/en-us/sql/t-sql/functions/datediff-transact-sql#:~:text=For%20a%20return%20value%20out%20of%20range%20for,days%2C%203%20hours%2C%2014%20minutes%20and%207%20seconds.
https://stackoverflow.com/questions/23630569/date-difference-formatted-in-days-hours-minutes-seconds
DECLARE @start DATETIME = '2018-04-12 15:53:33' , @end DATETIME = '2018-04-13 14:54:32' , @x INT; SET @x = DATEDIFF(s, @start, @end); SELECT CONVERT(VARCHAR(10), ( @x / 86400 )) + ' Days ' + CONVERT(VARCHAR(10), ( ( @x % 86400 ) / 3600 )) + ' Hours ' + CONVERT(VARCHAR(10), ( ( ( @x % 86400 ) % 3600 ) / 60 )) + ' Minutes ' + CONVERT(VARCHAR(10), ( ( ( @x % 86400 ) % 3600 ) % …
https://www.w3schools.com/SQl/func_sqlserver_datediff.asp
dayofyear = Day of the year; day, dy, y = Day; week, ww, wk = Week; weekday, dw, w = Weekday; hour, hh = hour; minute, mi, n = Minute; second, ss, s = Second; millisecond, ms = Millisecond; date1, date2: Required. The two dates to calculate the difference between
https://stackoverflow.com/questions/31746593/how-to-use-datediff-function-to-show-day-hour-minute-and-second
You can use modulus division on the output of the DATEDIFF() function for this: SELECT DATEDIFF(second,Depart_dt,Arrived_Dt)/(60*60*24) AS Day ,DATEDIFF(second,Depart_dt,Arrived_Dt)/(60*60)%24 AS Hour ,DATEDIFF(second,Depart_dt,Arrived_Dt)/(60)%60 AS Minute …
https://www.sqlservercentral.com/forums/topic/datediff-with-days-and-hours
To get the hours as a decimal. else its 6 days + 5 hours = 11 days and should be 6 days + .5 hours = 6.5 days. Not 100% sure this will work yet.
https://www.sqlshack.com/how-to-calculate-work-days-and-hours-in-sql-server/
https://social.msdn.microsoft.com/Forums/sqlserver/en-US/5e5a4474-31b8-4316-8a34-1e4a5572fb49/date-difference-in-dayshours-minutes-and-seconds
33 days, 4 hours, 5 mins ago ...or, to match the OP's request specific request of "2 days 1:00:00", you could use: select convert(varchar,DateDiff(dd, @dt1, @dt2) ) + ' days ' + convert(varchar,DateDiff(hh, @dt1, @dt2) % 24 ) + ':' + convert(varchar,DateDiff(mi, @dt1, @dt2) % 60 ) + ':' + convert(varchar,DateDiff(ss, @dt1, @dt2) % 60 )
https://www.sqlservertutorial.net/sql-server-date-functions/sql-server-datediff-function/
Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date.. date_part is the part of date e.g., a year, a quarter, a month, a week that you want to compare between the start_date and end_date.See the valid date parts in the table below. start_date and end_date are the dates to be compared.
http://sqlines.com/sql-server/functions/datediff
SQL Server DATEDIFF function returns the difference in seconds, minutes, hours, days, weeks, months, quarters and years between 2 datetime values. Quick Example: -- The difference is days between today and yesterday SELECT DATEDIFF(dd, GETDATE() - 1, GETDATE()); -- Returns: 1 -- The number of seconds in 24 hours SELECT DATEDIFF(ss, GETDATE() - 1, GETDATE()); -- Returns: 86400
https://dotnet.guide/developer/sql/get-difference-two-date-times-hours-sql-datediff.html
SQL Command. We used a DATEDIFF function to get our desired result. DATEDIFF function gives us the difference between given dates and also can convert that output to various other time formats like, Hours, Minutes, Seconds, Days etc.
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