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https://stackoverflow.com/questions/10482384/sql-server-2008-datediff-returns-wrong-value
The function DATEDIFF works with dates and for some reason, it thinks you're subtracting 6AM - Midnight (next day), which is 18 hours. The following code sample works fine for me in SQL 2008, so you need to check your data type to make sure you're using TIME and not DATETIME or SMALLDATETIME.
https://www.dotnetheaven.com/article/datediff-function-in-sql-server-2008
The DATEDIFF function is used to return the difference between two dates. It calculates the time between start and end time. Syntax. The syntax for using datediff () built-in function is given below: DATEDIFF (datepart,startdate,enddate) where, DatePart parameter is used to calculate the difference. The datepart can be one of the following ...
https://www.generacodice.com/en/articolo/454861/How-to-calculate-difference-in-hours-(decimal)-between-two-dates-in-SQL-Server
I have to calculate the difference in hours (decimal type) between two dates in SQL Server 2008. I couldn't find any useful technique to convert datetime to decimal with 'CONVERT' on MSDN. Can anybody help me with that? UPDATE: To be clear, I need the fractional part as well (thus decimal type). So from 9:00 to 10:30 it should return me 1.5.
https://www.w3schools.com/SQl/func_sqlserver_datediff.asp
Example. Return the difference between two date values, in hours: SELECT DATEDIFF (hour, '2017/08/25 07:00', '2017/08/25 12:45') AS DateDiff; Try it …
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