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https://stackoverflow.com/questions/12756769/sql-convert-datetime-and-subtract-hours
The query above that uses dateadd will always subtract 4 hours. If your goal is to convert an arbitrary datetime from UTC to local time, then it's more complicated because the offset that you need to add/subtract depends on the original datetime. A single value like -4 won't always work. Here are some ideas for dealing with the general case:
https://ycsoftware.net/add-and-subtract-hours-to-t-sql-datetime/
Add to 1 hour to the Current Date. DATEADD(hh,1,getdate()) Subtract 1 hour to the Current Date. DATEADD(hh,-1,getdate()) Add 1 hour to the Current Time and returns just the time part
https://www.tutorialspoint.com/how-to-subtract-3-hours-from-a-datetime-in-mysql
DATE_ADD. The query to subtract 3 hours from DateTime is as follows. With date_add, we have set a negative date −. mysql> select date_add(now(),interval -3 hour); The following is the output −.
https://stackoverflow.com/questions/30772434/how-to-subtract-hours-from-a-date-in-oracle-so-it-affects-the-day-also
I'm trying to subtract date from Oracle so it even effect the day as well. For example, if the timestamp is 01/June/2015 00 hours and if I subtract 2 hours, I want to be able to go to to 31/May/2014 22 hours. I tried. to_char(sysdate-(2/11), 'MM-DD-YYYY HH24') but it only subtracts the hour; it does not touch the day itself.
https://stackoverflow.com/questions/9711909/performing-date-time-subtraction-in-sql-server
i would like to know the difference between date/time ENTERED and date/time COMPLETED. for example. date entered = 1/1/2001 time entered = 10:00 time completed = 1/2/2001 time completed = 11:00 the difference is 25 hours. how can i perform this computation with a select statement? i just tried this:
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