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https://stackoverflow.com/questions/45156749/get-datediff-hours-in-decimal-sql-server
declare @start as time; declare @end as time; declare @total as decimal (18, 2); set @start = '17:00:00' set @end = '18:30:00' set @total = datediff (minute, @start, @end)/60 print @total. the query give me integer value, although the @total parameter is a decimal. I …
https://www.generacodice.com/en/articolo/454861/How-to-calculate-difference-in-hours-(decimal)-between-two-dates-in-SQL-Server
DATEDIFF(hour, start_date, end_date) will give you the number of hour boundaries crossed between start_date and end_date. If you need the number of fractional hours, you can use DATEDIFF at a higher resolution and divide the result: DATEDIFF(second, start_date, end_date) / 3600.0 The documentation for DATEDIFF is available on MSDN:
https://social.msdn.microsoft.com/Forums/sqlserver/en-US/efc1d44f-e964-48ba-a45a-333833540805/how-to-have-a-decimal-in-datediff
select cast(sql_variant_property(datediff(n, '6/1/2008 10:00:00 AM', '6/2/2008 10:10:00 AM'),'BaseType') as varchar(20)) returns: int Or, to see the type of numeric that your output is: declare @c sql_variant --your expression here select @c = datediff(n, '6/1/2008 10:00:00 AM', …
https://www.w3schools.com/SQl/func_sqlserver_datediff.asp
hour, hh = hour; minute, mi, n = Minute; second, ss, s = Second; millisecond, ms = Millisecond; date1, date2: Required. The two dates to calculate the difference between
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