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https://stackoverflow.com/questions/23630569/date-difference-formatted-in-days-hours-minutes-seconds#:~:text=UPDATED%20ANSWER%20%2804%2F12%2F2018%29%3A%20Accounts%20for%20difference%20in%20lower,divide%20to%20get%20the%20number%20of%20days%2C%20etc.
https://stackoverflow.com/questions/23630569/date-difference-formatted-in-days-hours-minutes-seconds
UPDATED ANSWER (04/12/2018): Accounts for difference in lower order date part that affects the higher order date part (i.e. 23 hour difference will now result in 0 days 23 hours)! DECLARE @start DATETIME = '2018-04-12 15:53:33' , @end DATETIME = '2018-04-13 14:54:32' , @x INT; SET @x = DATEDIFF(s, @start, @end); SELECT CONVERT(VARCHAR(10), ( @x / 86400 )) + ' Days ' + …
https://www.w3schools.com/SQl/func_sqlserver_datediff.asp
dayofyear = Day of the year; day, dy, y = Day; week, ww, wk = Week; weekday, dw, w = Weekday; hour, hh = hour; minute, mi, n = Minute; second, ss, s = Second; millisecond, ms = Millisecond; date1, date2: Required. The two dates to calculate the difference between
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