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https://lemmm.org/if-sally-can-paint-a-house/
If sally can paint a house. 2 hours and 24 minutes3 hours and 12 minutes3 hours and also 44 minutes4 hours and also 10 minutes or4 hours and also 33 minutes. You are watching: If sally can paint a house. (1/x is exactly how much that the house they deserve to paint with each other in one hour. Therefore x is the number of hours it will take lock both to pain the house)
https://softmath.com/algebra-word-problems/show.php?id=3785
sally can paint a house in 4 hours, each hour Sally paints 1/4 of the house. and john can paint the same house in 6 hours, each hour John paints 1/6 of the house. If they work together, each hour they paint 1/4 + 1/6 of the house. The time they need to finish the job is 1/ (1/4+1/6) = 1/ (5/12) = 12/5 = 2 2/5 hours.
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https://www.toppr.com/ask/question/if-sally-can-paint-a-house-in-4-hours-and-john-can-paint-the-same/
4 hours and 33 minutes. Answer. Correct option is. A. 2 hours and 24 minutes. In 1hour , sally can paint 1/4th house. In 1hour , john can paint 1/6th house. In 1hour they both combined can paint 1/4+1/6=5/12th house. So they both combined can paint the house in 12/5hour which implies 2hours and 24minutes.
https://math.answers.com/Q/If_Sally_can_paint_a_house_in_4_hours_and_John_can_paint_the_same_house_in_6_hours_how_long_will_it_take_for_both_of_them_to_paint_the_house_together
Sally does 1 job in 4 hours ===> 1/4th of the job per hour.John does 1 job in 6 hours ===> 1/6th of the job per hour.Working together, they do (1/4 + 1/6) = (3/12 + 2/12) = 5/12 job per hour.The...
https://www.freemathhelp.com/forum/threads/word-prob-if-sally-can-paint-a-house-in-four-hours.56423/
2--B can paint the house in 3 hours. 3--A's rate of painting is 1 house per A hours (5 hours) or 1/A (1/5) houses/hour. 4--B's rate of painting is 1 house per B hours (3 hours) or 1/B (1/3) houses/hour. 5--Their combined rate of painting is 1/A + 1/B (1/5 + 1/3) = (A+B)/AB (8/15) houses /hour.
https://math.answers.com/Q/If_sally_can_paint_a_house_in_four_hours_and_john_can_paint_the_same_house_in_6_hours_how_long_will_it_take_for_both_of_them_to_paint_the_house_together
John can paint 1/6 of a house per hour.Let's say the answer is t hours for the total job.Then (1/4)t + (1/6)t = 1(1/4 + 1/6)t = 1(6/24 + 4/24)t = 1(10/24)t = 1t = …
https://www.quora.com/If-Sally-can-paint-a-house-in-4-hours-and-John-can-paint-the-same-house-in-6-hours-how-long-will-it-take-for-both-of-them-to-paint-the-house-together
If Sally can do one house in four hours, then she can do 1.5 houses in the six hours it takes John. 1 house + 1.5 houses = 2.5 houses in 6 hours. 6 hours per 2.5 houses = 6 / 2.5 = 2.4 hours per house, working together. So the answer is 2 hours, 24 minutes.
https://www.quora.com/5-If-Sally-can-paint-a-house-in-3-hours-and-John-can-paint-the-same-house-in-6-hours-how-long-will-it-take-for-both-to-paint-a-house
Answer (1 of 4): 2 hours If sally paints the house in 3 hours, then fraction of house painted in 1 hour=1/3 If john paints the house in 6 hours , then fraction of house painted in 1 hour=1/6 Therefore total fraction of house painted in 1 hour=1/3+1/6=1/2. Therefore total time taken to paint...
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