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https://stackoverflow.com/questions/2022334/group-and-count-in-rails
The debug method won't show the count because it's not an ActiveRecord attribute, but there is a count attribute on each object. In any case, Chandra's solution is much better. In any case, Chandra's solution is much better.
https://stackoverflow.com/questions/736253/time-difference-in-hours
Rails 6.1 introduces new ActiveSupport::Duration conversion methods like in_seconds, in_minutes, in_hours, in_days, in_weeks, in_months, and in_years. As a result, now, your problem can be solved as: date_1 = Time.parse('2020-10-19 00:00:00 UTC') date_2 = Time.parse('2020-10-19 03:35:38 UTC') (date_2 - date_1).seconds.in_hours.to_i # => 3
https://api.rubyonrails.org/classes/DateAndTime/Calculations.html
end_of_week (start_day = Date.beginning_of_week) Link. Returns a new date/time representing the end of this week on the given day. Week is assumed to start on start_day, default is Date.beginning_of_week or config.beginning_of_week when set. DateTime objects have their time set to 23:59:59.
https://apidock.com/rails/ActiveRecord/Calculations/ClassMethods/count
Count operates using three different approaches. Count all: By not passing any parameters to count, it will return a count of all the rows for the model.; Count using column: By passing a column name to count, it will return a count of all the rows for the model with supplied column present ; Count using options will find the row count matched by the options used.
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https://stackoverflow.com/questions/9572860/count-number-of-days-between-two-dates
A full answer would convert to_i and then divide: (Time.now.to_i - 23.hours.ago.to_i) / 86400 >> 0 (Time.now.to_i - 25.hours.ago.to_i) / 86400 >> 1 (Time.now.to_i - 1.day.ago.to_i) / 86400 >> 1. In the question's specific example, one should not parse to Date if the time passed is relevant. Use Time.parse instead.
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