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https://www.postgresqltutorial.com/postgresql-age/
Introduction to PostgreSQL age () function. We typically have to calculate ages in business applications e.g., ages of people, years of services of employees, etc. In PostgreSQL, you can use the AGE () function to achieve these tasks. The following illustrates the syntax of the AGE () function: The AGE () function accepts two TIMESTAMP values.
https://www.techonthenet.com/postgresql/functions/age.php
Let's look at some PostgreSQL age function examples and explore how to use the age function in PostgreSQL. For example: postgres=# SELECT age (timestamp '2014-01-01'); (current date is '2014-04-25') age ---------------- 3 mons 24 days (1 row) postgres=# SELECT age (timestamp '2014-04-25', timestamp '2014-01-01'); age ---------------- 3 mons 24 days (1 row) postgres=# SELECT …
https://www.w3resource.com/PostgreSQL/age-function.php
Example 1: PostgreSQL AGE() function. The example below finds the age between two dates specified in the argument. Code. SELECT age(timestamp '2015-01-15', timestamp '1972-12-28'); Sample Output: age ----- 42 years 18 days (1 row) Example 2: The example below finds the age between current date and the date as specified in the argument. Code. SELECT …
https://www.postgresql.org/docs/current/functions-datetime.html
PostgreSQL 's approach uses the month from the earlier of the two dates when calculating partial months. For example, age('2004-06-01', '2004-04-30') uses April to yield 1 mon 1 day, while using May would yield 1 mon 2 days because May has 31 days, while April has only 30. Subtraction of dates and timestamps can also be complex.
https://www.postgresql.org/docs/8.4/functions-datetime.html
PostgreSQL 's approach uses the month from the earlier of the two dates when calculating partial months. For example, age('2004-06-01', '2004-04-30') uses April to yield 1 mon 1 day , while using May would yield 1 mon 2 days because May has 31 days, while April has only 30.
https://stackoverflow.com/questions/36913931/postgresql-how-to-change-the-age-format-in-the-output
I have a patient_age column in patient table and the format of the age in that column will be like this, 10D8M45Y (It means 10 Days 8 Months 45 Years) I need a Postgresql Query which can give the output like this, 45 Years 8 Months 10 Days Thank You.
https://www.educba.com/postgresql-interval/
Introduction to PostgreSQL Interval. We can store and manage the time period in seconds, minutes, hours, days, months, years, etc., by using the interval data type provided by PostgreSQL. The interval value is quite easy to understand, and it is human-readable. The interval value needs 16 bytes storage size, which stores a period with a low value of -178000000 years and a high …
http://www.sqlines.com/postgresql/how-to/datediff
In PostgreSQL, you can use an expression to define the number of days (see above), multiple by 24 and add the difference is hours. PostgreSQL : -- Difference between Dec 30, 2011 08:55 and Dec 30, 2011 9:05 in weeks SELECT DATE_PART ( 'day' , '2011-12-30 08:55' :: timestamp - '2011-12-30 09:05' :: timestamp ) * 24 + DATE_PART ( 'hour' , '2011-12-30 08:55' :: timestamp - '2011 …
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