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http://dba-oracle.com/t_add_hours_to_oracle_date.htm#:~:text=Answer%3A%20To%20add%20hours%20to%20an%20Oracle%20date,1%20is%20one%20day%20ahead%20%28exactly%2024%20hours%29
https://stackoverflow.com/questions/30167311/pl-sql-adding-hours-to-timestamp-parameter
to_timestamp (dateFrom,'mm/dd/yyyy hh24:mi:ss') (substitute the appropriate mask based on the format of your input parameter) Then just add 7/24. to_timestamp (dateFrom,'mm/dd/yyyy hh24:mi:ss') + 7/24; Adding 1 adds a full day, so adding 1/24 adds 1 hour. This can also be done with the INTERVAL operator:
https://www.tutorialspoint.com/plsql/plsql_date_time.htm
https://blogs.oracle.com/oraclemagazine/post/working-with-dates-in-plsql
Here are the answers to the PL/SQL Challenge questions in last issue’s “Working with Numbers in PL/SQL” article: Answer 1: The plch_ceil_and_floor function always returns either 1 or 0: 0 if the number passed to the function is an integer, 1 otherwise. Answer 2: (a) and (b) are correct; (c) is incorrect.
https://stackoverflow.com/questions/52658426/oracle-sql-adding-hours-to-a-date
Starting with the date/time of July 20, 2001 10:40:12, display the following result table. Use the Dual table. subtract 2 days Result :18-jul-01 10:40:12. add half a day Result: 20-jul-01 22:40:12. add 4and half hours Result: 20-jul-01 15:10:12
http://dba-oracle.com/t_add_hours_to_oracle_date.htm
The formula (1/24*5) is explained as follows: sysdate + 1 is one day ahead (exactly 24 hours) - divided by 24 gives one hour. * 5 multiply by 5 to get the 5 hours. You can also add 5 hours to a date this way: (60 * 5) select sysdate, sysdate + interval '300' "5 hours" from dual; As we see, there are several ways to add hours to an Oracle date column.
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