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https://stackoverflow.com/questions/26510033/oracle-add-1-hour-in-sql
SELECT DATE_COLUMN + 1 is adding a day SELECT DATE_COLUMN + N /24 to add hour (s) - N being number of hours SELECT DATE_COLUMN + N /1440 to add minute (s) - N being number of minutes SELECT DATE_COLUMN + N /86400 to add second (s) - N being number of seconds. Using INTERVAL:
https://community.oracle.com/tech/developers/discussion/1005710/dateadd-in-plsql
Dec 20, 2009 9:50AM edited Dec 20, 2009 10:33AM in SQL & PL/SQL I'm in the processw of converting TSQL to PLSQL and come across a slight problem. DATEADD(MONTH, @months * -1, GETDATE())
https://www.tutorialspoint.com/plsql/plsql_date_time.htm
PL/SQL - Date & Time, In this chapter, we will discuss the Date and Time in PL/SQL. There are two classes of date and time related data types in PL/SQL − ... HOUR: 00 to 23: 0 to 23: MINUTE: 00 to 59: 0 to 59: SECOND: 00 to 59.9(n), where 9(n) is the precision of time fractional seconds.
https://www.w3schools.com/sqL/func_sqlserver_dateadd.asp
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https://docs.oracle.com/cd/E41183_01/DR/Dateadd.html
Return(DateAdd ("09/138", "I" , , , -3)) 06/139. The given date (09/138) using date format I is May 18, 2009. Subtracting three years results in the date May 18, 2006. Because 2008 is a leap year, the correct day of the year (counting consecutively from January 1) is 139. The resulting date is returned in the same date format.
https://blogs.oracle.com/oraclemagazine/post/working-with-dates-in-plsql
Here are the answers to the PL/SQL Challenge questions in last issue’s “Working with Numbers in PL/SQL” article: Answer 1: The plch_ceil_and_floor function always returns either 1 or 0: 0 if the number passed to the function is an integer, 1 otherwise. Answer 2: (a) and (b) are correct; (c) is incorrect.
https://social.msdn.microsoft.com/Forums/sqlserver/en-US/611fabfb-3648-423d-9c41-5a77259dcdb1/using-dateadd-to-increment-hours-and-minutes
To add (in this case) 23 hours, 59 minutes, 59 seconds to a date parameter: =DATEADD(DateInterval.Hour,23,DateAdd(DateInterval.minute,59,DateAdd(DateInteval.second,59,Parameters!dt_DATEOFISSUE.Value))) Jens
https://www.sqlshack.com/how-to-calculate-work-days-and-hours-in-sql-server/
Figure 4. Again, just as in the calculation of days, the output of the week calculation – 2 weeks – is incorrect. This time the issue is as a result of the way that WEEK interval works within the DATEDIFF function. The WEEK interval in DATEDIFF does not actually calculate the number of weeks, instead it calculates the number of instances that a complete weekend …
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