If Sally Can Paint A House In 4 Hours

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If Sally can paint a house in 4 hours, and John can paint ...

    https://www.toppr.com/ask/question/if-sally-can-paint-a-house-in-4-hours-and-john-can-paint-the-same/
    4 hours and 33 minutes. Answer. Correct option is. A. 2 hours and 24 minutes. In 1hour , sally can paint 1/4th house. In 1hour , john can paint 1/6th house. In 1hour they both combined can paint 1/4+1/6=5/12th house. So they both combined can paint the …

Word prob: If Sally can paint a house in four hours ...

    https://www.freemathhelp.com/forum/threads/word-prob-if-sally-can-paint-a-house-in-four-hours.56423/
    Aug 08, 2008 · This type of problem is usually best solved by considering what happens in one unit of time. In this case the unit of time is an hour. One of them can do the entire job in 4 hours, so in one hour 1/4 of the job is done. The other can do the job in 6 hours so in one hour he/she can do …

If Sally can paint a house in 4 hours, and John can paint ...

    https://www.jiskha.com/questions/106308/if-sally-can-paint-a-house-in-4-hours-and-john-can-paint-the-same-house-in-6-hours-how
    May 27, 2008 · 1--A can paint a room in 5 hours. 2--B can paint a room in 3 hours. 3--A's rate of painting is 1 room per A hours (5 hours) or 1/A (1/5) room/hour. 4--B's rate of painting is 1 room per B hours (3 hours) or 1/B (1/3) room/hour. 5--Their combined rate of painting is therefore 1/A + 1/B = (A+B)/AB = (1/5 + 1/3) = (8/15) rooms /hour.

Sally can paint a house in 4 hours. can paint a house in 6 ...

    https://www.justanswer.com/math-homework/1pbbk-sally-paint-house-hours-john-paint-house.html
    Jan 07, 2009 · John can paint 1/6 of a house in an hour Sally can paint 1/4 of a house in an hour Their combined rate is 1/6 + 1/4 = 2/12 + 3/12 = 5/12 houses per hour work = rate * time 1 = 5/12 * time Now solve for time 1/ (5/12) = time 12/5 =time 12/5 = 2 and 2/5 2/5 of an hour is 24 minutes, so It will take them 2 hours and 24 minutes together.Estimated Reading Time: 5 mins

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