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https://physics.stackexchange.com/questions/28563/hours-of-light-per-day-based-on-latitude-longitude-formula#:~:text=Number%20of%20hours%20of%20sunlight%20on%20nth%20day,that%20day%20that%20has%2012%20hours%20of%20sunlight.
https://physics.stackexchange.com/questions/28563/hours-of-light-per-day-based-on-latitude-longitude-formula
Day Length (hours) = 2 * ha / 15, (equation 1) where ha is the hour angle of sunrise (sunset) from noon and is equal to ( http://www.jgiesen.de/astro/suncalc/calculations.htm ): ha = arccos (cos(90.833) /(cos(L)*cos(δ)) - tan(L)*tan(δ)) .
https://www.dummies.com/education/math/trigonometry/use-the-sine-to-show-the-number-of-daylight-hours-in-a-location/
Letting t be the day of the year (from 1 to 365), you can figure the number of hours of sunlight, H, if you enter a value for t in the equation H ( t) = 2.4 sin (0.017 t – 1.377) + 12. The following figure shows the graph of this equation. The number of hours of sunlight, H, in San Diego on Day t.
https://stackoverflow.com/questions/6372802/calculate-daylight-hours-based-on-gegraphical-coordinates
Here is a python function that returns the number of hours of daylight with arguments of latitude and day of the year (number between 1-356): import math def Daylight (latitude,day): P = math.asin (0.39795 * math.cos (0.2163108 + 2 * math.atan (0.9671396 * math.tan (.00860 * (day - 186))))) pi = math.pi daylightamount = 24 - (24 / pi) * math.acos ( …
https://worldbuilding.stackexchange.com/questions/167877/how-do-i-calculate-the-hours-of-daylight-on-an-arbitrary-planet-for-a-given-day
r = length of local day in decimal Earth hours; This formula calculates the length of day in decimal Earth hours (not including astronomical refraction (which causes twilight), solar disc diameter, or elevation of the observer) for planets (not including moons) with day lengths shorter than their year lengths that are not tidally locked.
https://www.had2know.com/society/sunrise-sunset-time-calculator-formula.html
H = | (1/15)*arccos [ -tan (L)*tan (23.44*sin (360 (D+284)/365))] |. For the time of sunset, the equation is the same, but it is H hours after the local noon. Example: Suppose it is April 15 and a person is 40° south of the equator. Thus, L = 40 and D = 105.
https://www.maas.museum/observations/2007/10/30/how-to-calculate-sunrise-and-set-a-worked-example/
cos H = cos 90°50’.sec λ. sec δ – tan λ . tan δ =-.018046 – .16666 =-.18471. H = 100°.644 = 6hours 42 minutes 35 seconds. On 31 October 2007 the Sun is due north at 11h 43m 40” at the standard meridian. For Sydney’s longitude subtract …
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