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https://www.grc.nasa.gov/WWW/k-12/Numbers/Math/Mathematical_Thinking/sun12.htm
(since mW = mJ/sec). If the sun were always directly overhead, the amount of energy incident upon a 1 cm 2 solar collector oriented perpendicular to the sun's rays in 12 hours would be (137 mW/cm 2) x (1 cm 2) x (4.3 x 104 sec.) = 5.9 x 106 mJ. But we know that the sun is usually not directly overhead.
https://www.youtube.com/watch?v=aApnZaJi0NE
10 HOURS VERSION"The Sun is playing a secret melody, hidden inside itself, that produces a widespread throbbing motion of its surface. The sounds are coursin...
https://www.jma.go.jp/jma/jma-eng/jma-center/ric/Our%20activities/International/CP7-Sunshine.pdf
Usually, this is equivalent to subtracting 0.1 hours from the length of each burn trace. (b) If the burn trace has a circular form, take the radius as its length. If there are multiple circular burns, count two or three as a sunshine duration of 0.1 hours, and four, five or six as 0.2 hours. Count sunshine duration this way in increments of 0.1 hours.
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