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https://stackoverflow.com/questions/24328346/difference-between-time-columns-in-sql#:~:text=In%20DB2%20the%20result%20of%20the%20subtraction%20of,time%20%2700%3A53%3A00%27%20obviously%20gives%20a%20negative%20value%20-230600.
https://stackoverflow.com/questions/53181875/sqldb2-difference-between-two-dates-in-hours-using-timestampdiff-and-cast
Column1 with start_date: 2001-07-11-16.51.40.000000. Column2 with end_date: 2001-07-12-09.21.54.000000. Output: 75301 7h 53min 01sec 7.88. I try something like this. SELECT START_DATE, END_DATE CAST (TIMESTAMPDIFF (HOUR, START_DATE, END_DATE)) AS TIME FROM TABLE; sql casting db2 difference timestampdiff. Share.
https://www.ibmmainframer.com/db2-tutorial/db2-sql-date-time-functions/
How to get current date, time and timestamp ? SELECT current date FROM …
https://www.dev-notes.com/blog/2010/08/11/calculating-the-difference-between-two-dates-or-times-in-db2/
To do so, we can utilize the timestampdiff() function provided by DB2. This function takes in two parameters. The first parameter is a numeric value indicating the unit in which you wish to receive the results in; the values must be one of the following. 1 : Fractions of a second; 2 : Seconds; 4 : Minutes; 8 : Hours; 16 : Days; 32 : Weeks; 64 : Months
https://www.ibm.com/docs/SSEPGG_11.5.0/com.ibm.db2.luw.sql.ref.doc/doc/r0000861.html
Hours: 0-24 or blank-6 to -5: Minutes: 0-59 or blank-4 to -3: Seconds: 0-59-2 to -1: Decimal Points: Period: 0: Microseconds: 000000-999999: 1 to 6
https://www.db2tutorial.com/db2-basics/db2-time/
The TIME type represents a time of day that consists of three parts: hours, minutes, and seconds. A TIME value ranges from 00.00.00 to 24.00.00. The following shows the syntax of the time type: TIME. Code language: SQL (Structured Query Language) (sql) Internally, DB2 uses three bytes to store a time value.
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https://www.sqltutorial.org/sql-date-functions/sql-datediff/
Notice that the DATEDIFF () function takes the leap year into account. As shown clearly in the ...
https://www.ibm.com/support/pages/how-calculate-difference-between-two-dates-resulting-days-months-or-years
*Subtract the two date values, divide by (60 seconds * 60 minutes * 24 hours * 365.25 days / 12 months). COMPUTE month1 = (date2 - date1) / (60 * 60 * 24 * 365.24 / 12) . EXE . *You may also use the DATEDIFF function. COMPUTE month2 = DATEDIFF(date2,date1,"month"). EXE. C. Examples of Results in Years
https://bytes.com/topic/db2/answers/834777-how-calculate-date-time-difference-db2
calculation, you can use the following to determine the difference in time (in seconds): (DAYS(t1) - DAYS(t2)) * 86400 + (MIDNIGHT_SECONDS(t1) - MIDNIGHT_SECONDS(t2)) For convenience, you can also create an SQL user-defined function of the above: CREATE FUNCTION secondsdiff(t1 TIMESTAMP, t2 TIMESTAMP) RETURNS INT RETURN ((DAYS(t1) - …
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