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https://stackoverflow.com/questions/53181875/sqldb2-difference-between-two-dates-in-hours-using-timestampdiff-and-cast
Nov 07, 2018 · TIME in SQL (and DB2 in particular) isn't a duration, it's "time of day", so you can't cast it.TIMESTAMPDIFF will give you the total amount of any one unit, which means you'd have to call it multiple times (once for hours, once for minutes after subtracting hours, ....), but it has a serious flaw: for any two dates more than one month apart, the value will not be correct, by about 24 hours/month.
https://www.ibm.com/support/producthub/db2/docs/content/SSEPGG_11.5.0/com.ibm.db2.luw.sql.ref.doc/doc/r0000861.html
IBM Db2; TIMESTAMPDIFF scalar function. Returns an estimated number of intervals of the type defined by the first argument, based on the difference between two timestamps. ... hours + ((days+(months*30)+(years*365))*24) Minutes (the absolute value of the duration must not exceed 40850913020759.999999)Days: + (months*30)+ (years*365)
https://www.dev-notes.com/blog/2010/08/11/calculating-the-difference-between-two-dates-or-times-in-db2/
Aug 11, 2010 · Calculating the difference between two dates or times in DB2. To do so, we can utilize the timestampdiff () function provided by DB2. This function takes in two parameters. The first parameter is a numeric value indicating the unit in which you wish to receive the results in; the values must be one of the following. 1 : Fractions of a second.
https://stackoverflow.com/questions/52875513/datediff-in-db2-query
Oct 17, 2018 · The query now fails on DB2 due to the line below, saying that DATEDIFF cannot be found. I'm assuming only because this isn't a valid function on db2. Is there an equivalent to this on DB2 that will maintain performance as well as function?
https://www.ibm.com/support/pages/how-calculate-difference-between-two-dates-resulting-days-months-or-years
Jun 16, 2018 · EXE . *You may also use the DATEDIFF function. COMPUTE month2 = DATEDIFF (date2,date1,"month"). EXE. C. Examples of Results in Years. Examples of Result in years (Can be used to calculate the age) *Subtract the two date values, divide by (60 seconds * 60 minutes * 24 hours * 365.25 days) COMPUTE year1 = (date2 - date1) / (60 * 60 * 24 * 365.24 ...
https://developer.ibm.com/articles/fun-with-dates-and-times/
Aug 28, 2003 · Why the 2,000 year difference in the above results? When the DATE function gets a character string as input, it assumes that it is valid character representation of a DB2 date, and converts it accordingly. By contrast, when the input is numeric, the function assumes that it represents the number of days minus one from the start of the current era (that is, 0001-01-01).
https://www.db2tutorial.com/db2-date-functions/
This section introduces you to some common Db2 date functions that help you manipulate date and time data effectively. Function. Description. ADD_DAYS. Returns a datetime value that represents the first argument plus a specified number of days. ADD_HOURS.Estimated Reading Time: 6 mins
https://ibmmainframes.com/about39506.html
Apr 07, 2009 · DB2: I wanted to find the difference between two dates such that the result is in years For Eg: '2001-12-31' - '2000-01-01' ~ 2yrs When...
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