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https://stackoverflow.com/questions/53181875/sqldb2-difference-between-two-dates-in-hours-using-timestampdiff-and-cast
TIME in SQL (and DB2 in particular) isn't a duration, it's "time of day", so you can't cast it. TIMESTAMPDIFF will give you the total amount of any one unit, which means you'd have to call it multiple times (once for hours, once for minutes after subtracting hours, ....), but it has a serious flaw: for any two dates more than one month apart, the value will not be correct, by about 24 hours/month.
https://www.dev-notes.com/blog/2010/08/11/calculating-the-difference-between-two-dates-or-times-in-db2/
To do so, we can utilize the timestampdiff() function provided by DB2. This function takes in two parameters. The first parameter is a numeric value indicating the unit in which you wish to receive the results in; the values must be one of the following. 1 : Fractions of a second; 2 : Seconds; 4 : Minutes; 8 : Hours; 16 : Days; 32 : Weeks; 64 : Months
https://stackoverflow.com/questions/52875513/datediff-in-db2-query
The query now fails on DB2 due to the line below, saying that DATEDIFF cannot be found. I'm assuming only because this isn't a valid function on db2. Is there an equivalent to this on DB2 that will maintain performance as well as function?
https://www.db2tutorial.com/db2-date-functions/
This section introduces you to some common Db2 date functions that help you manipulate date and time data effectively. Function. Description. ADD_DAYS. Returns a datetime value that represents the first argument plus a specified number of days. ADD_HOURS.
https://www.ibm.com/docs/SSEPGG_11.5.0/com.ibm.db2.luw.sql.ref.doc/doc/r0000861.html
Hours: 0-24 or blank-6 to -5: Minutes: 0-59 or blank-4 to -3: Seconds: 0-59-2 to -1: Decimal Points: Period: 0: Microseconds: 000000-999999: 1 to 6
https://www.ibm.com/support/pages/how-calculate-difference-between-two-dates-resulting-days-months-or-years
*Subtract the two date values, divide by (60 seconds * 60 minutes * 24 hours * 365.25 days / 12 months). COMPUTE month1 = (date2 - date1) / (60 * 60 * 24 * 365.24 / 12) . EXE . *You may also use the DATEDIFF function. COMPUTE month2 = DATEDIFF(date2,date1,"month"). EXE. C. Examples of Results in Years
https://ibmmainframes.com/about39506.html
DB2: I wanted to find the difference between two dates such that the result is in years For Eg: '2001-12-31' - '2000-01-01' ~ 2yrs When...
https://www.tek-tips.com/viewthread.cfm?qid=294977
In Orcale there is a function MONTHS_BETWEEN and in SQL Server DateDiff which help to calculate age from a birthdate. Is there a similar function in DB2 to get date difference in SQL - IBM: DB2 - …
https://www.linkedin.com/in/sekhar-mekala
DB2 V8.1, z/OS 1.7, REXX, COBOL, JCL, ERWIN, IBM DB2 Utilities, VSS (Visual Source Safe) ... process has drastically reduced the “Refresh time” from 24 hours to 6 hours.
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