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https://support.microsoft.com/en-us/office/datediff-function-e6dd7ee6-3d01-4531-905c-e24fc238f85f
SELECT DateDiff("h",[DateTime],Date()) AS DaysSinceSale FROM ProductSales; Returns the difference between the system date and "DateTime" as number of 'Hours' and displays in the column "DaysSinceSale". SELECT DateDiff("n",[DateTime],Date()) AS DaysSinceSale FROM ProductSales;
https://stackoverflow.com/questions/35840300/datediff-hours-and-minutes
For Hours AND minutes, you can use this example: DECLARE @start datetime , @end datetime SELECT @start = '2009-01-01' , @end = DateAdd(mi, 52, DateAdd(hh, 18, DateAdd(dd, 2, @start))) SELECT @start , @end SELECT DateDiff(dd, @start, @end) As days , DateDiff(hh, @start, @end) % 24 As hours , DateDiff(mi, @start, @end) % 60 As mins
https://www.w3schools.com/Sql/func_msaccess_datediff.asp
Example. Return the difference between a specified date and today's date, in days: SELECT DateDiff ("d", #13/01/1998#, Date ()); Try it Yourself ». MS Access Functions.
https://community.powerbi.com/t5/Desktop/DATEDIFF-HOURS-AND-MINUTES/td-p/1779589
This will give you duration. [LOG Booking Start Time (Changed To)] - [LOG Booking End Time (Changed To)] or divide by 60. 2b MINS) Scheduled Duration Hours = DATEDIFF ( [LOG Booking Start Time (Changed To)], [LOG Booking End Time (Changed To)],MINUTE)/60. or convert it like hh:mm.
https://www.bigresource.com/MS_ACCESS-datediff-minutes-and-hours-xw65D9mQ.html
The number of hours between 18:00 hours (6:00 p.m.) and 24:00 hours (12 a.m.) should be 6 hours. Access and Excel are both returning a datediff value of 18 hours. If I change the end time to 12 p.m. (12:00 hours), then Access/Excel returns 6 hours but midnight is …
https://www.access-programmers.co.uk/forums/threads/datediff-minutes-and-hours.101441/
71. Feb 3, 2006. #1. I would like to calculate the time difference between two dates, what ive got so far is. TimeSpent: DateDiff ("n", [datein], [dateout]) This calculates the minutes between two dates, Can you format this so that it calculates hours. minutes for example 124 minutes would be 2.04?
http://allenbrowne.com/casu-13.html
You must use "n" for DateDiff() to return minutes: "m" returns months. To display this value as hours and minutes on your report, use a text box with this Control Source: =[Minutes] \ 60 & Format([Minutes] Mod 60, "\:00") This formula uses: the integer division operator (\) …
https://answers.microsoft.com/en-us/msoffice/forum/all/calculate-the-difference-between-two-times-in/0b383396-3cd4-4987-bb4c-fc29a3f2941c
You need to understand that Access stores time as a double precision number where the integer portion is the number of days since 12/30/1899 and the decimal portion a fraction of a day. So that .25 would be 6 AM (or 6 hours). If you use this: =(Stoptime - Starttime)*24 it should also work. To use your numbers 10:00-09:30 would = 0.0208333.
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