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https://www.jiskha.com/questions/431281/a-satellite-with-an-orbital-period-of-exactly-24-0-h-is-always-positioned-over-the-same
Mar 28, 2011 · A satellite with an orbital period of exactly 24.0 h is always positioned over the same spot on Earth. This is known as a geosynchronous orbit. Television, communication, and weather satellites use geosynchronous orbits. At what distance would a satellite have to orbit Earth in order to have a geosynchronous orbit?
https://study.com/academy/answer/a-geostationary-earth-orbiting-satellite-has-an-orbital-period-of-24-hours-the-same-as-the-rotation-period-of-earth-so-that-it-is-always-above-the-same-location-on-the-planet-assuming-a-circular-orbit-how-far-above-the-earth-s-surface-is-such-a-satellit.html
A geostationary Earth-orbiting satellite has an orbital period of {eq}24 {/eq} hours, the same as the rotation period of Earth so that it is always above the same location on the planet.
https://www.numerade.com/questions/a-communications-satellite-with-a-24-hour-period-hovers-over-a-fixed-point-on-earth-and-to-earth-obs/
A communications satellite with a 24 -hour period hovers over a fixed point on Earth and, to Earth observers, seems motionless. ... A satellite with an orbital period of exactly $24.0… 01:32. Why are satellites normally sent into orbit by firing them in an easterly di… 01:07. If a satellite in a circular orbit above Earth is continually ...
https://earthobservatory.nasa.gov/features/OrbitsCatalog/page2.php
A satellite at this height takes 12 hours to complete an orbit. As the satellite moves, the Earth rotates underneath it. In 24-hours, the satellite crosses over the same two spots on the equator every day. This orbit is consistent and highly predictable. It is the orbit used …Author: Holli Riebeek
https://socratic.org/questions/calculate-the-height-from-the-earth-s-surface-that-a-satellite-must-attain-in-or
Jan 12, 2018 · Geosynchronous means that the satellite has same period as the earth, back to the same place in 24 hours. T =24hrs = 86400 s. And let h = height of the satellite from the surface of the earth. r = radius of the satellite from the center of the Earth #R_E# = earth radius #M_E# = …
https://en.wikipedia.org/wiki/Ground_track
A satellite whose orbital period is an integer fraction of a day (e.g., 24 hours, 12 hours, 8 hours, etc.) will follow roughly the same ground track every day. This ground track is shifted east or west depending on the longitude of the ascending node, which can vary over time due to perturbations of the orbit. If the period of the satellite is slightly longer than an integer fraction of a day ...
https://keisan.casio.com/exec/system/1224665242#!
calculate orbital period / ground speed of a satellite for which I am adapting equipment [2] 2021/06/19 00:13 30 years old level / An office worker / A public employee / Very / Purpose of use Quicker than doing the math myself :) [3] 2021/06/09 21:49 50 years old level / A teacher / A researcher / Useful /
https://physicsmastered.com/2012/08/12/what-is-its-orbital-period/
Aug 12, 2012 · An earth satellite moves in a circular orbit at a speed of 7000m/s? What is its orbital period? r = GM/v 2 r: distance of the satellite from the center of Earth in m M is the mass of Earth: 5.974 x 10 24 v is the orbital speed: 7000 m/s. r = 6.674x 10-11 x 5.974 x 10 24 /7000 2 r = 8137445 meters from the center of the Earth and : 8137445 – 6378100 = 1749345 meters from the surface of the ...
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