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https://softmath.com/algebra-word-problems/show.php?id=16351
128mi=(R-C)(4 hours) Where 'R' is the rate of the boat and 'C' is the rate of the current) Downstream: 128mi=(R+C)(2 hours) Where 'R' is the rate of the boat and 'C' is the rate of the current) Using Algebrator to solve for 'R' and 'C', we get: C=16 mph. R=48 mph
https://www.algebra-online.com/math-word-problems/a-motorboat-takes-4-hours-to-travel-192-km-going-upstream
t1 = 4 hr the time of the travel upstream. t2 = 3 hr the time of the travel downstream. d =192 km the distance traveled in each direction. v = rate of the boat in still water, v>0. r = the rate of the river. We know that speed = distance/time. Traveling upstream the rate of the boat is: v - r. v - …
https://www.algebra.com/algebra/homework/Length-and-distance/Length-and-distance.faq.question.923643.html
https://www.jiskha.com/questions/831/a-motor-boat-took-4-hours-to-make-a-downstream-trip-with-a-current-of-3mph-the-return
A motor boat took 4 hours to make a downstream trip with a current of 3mph. The return trip against the same current took 8 hours. Find the speed of the boat in still water. Call Y the boat's rate. distance = rate x time. downstream rate of boat is Y+3. t=4 hrs. upstream rate of boat is Y - 3. t=8 hrs. d(downstream) = (Y+3)4 d(upstream) = (Y-3)8
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