A Canoeist Paddled For 4 Hours

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SOLUTION: A canoeist paddled for 4 hours with a 6-km/h ...

    https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.694674.html
    SOLUTION: A canoeist paddled for 4 hours with a 6-km/h current to reach a campsite. The return trip against the same current took 10 hours. Find the speed of the canoe in still water.

A canoeist paddled for 2 hours with a 7 -km/h current ...

    https://www.chegg.com/homework-help/questions-and-answers/canoeist-paddled-2-hours-7-km-h-current-reach-campsite-return-trip-current-took-9-hours-fi-q63323540
    A canoeist paddled for 2 hours with a 7 -km/h current to reach a campsite. The return trip against the same current took 9 hours. Find the speed of the canoe in still water. Complete the table.

A canoeist took 2 hours to paddle 12 km down a river. The ...

    https://www.quora.com/A-canoeist-took-2-hours-to-paddle-12-km-down-a-river-The-return-trip-against-the-current-took-3-hours-What-was-the-paddling-speed-of-the-canoeist-in-still-water
    Given: Distance travelled upstream and downstream =24 kilometers, time taken upstream is 4 hours and time taken downstream is 2 hours. Required: speed in still water and speed of current. Upstream: Distance =24 km; time =4 hours; speed is (x-y); 24=(x-y)(4)=4x-4y Eq 1. Downstream: Distance =24 km; time is 2 hours; speed is (x+y); 24= (x+y)(2)=2x+2y Eq 2

algebra precalculus - I am confused about rates in this ...

    https://math.stackexchange.com/questions/3677306/i-am-confused-about-rates-in-this-word-problem
    May 16, 2020 · My answer: Let x be the rate in still water. Rate upstream = (x-2). Rate downstream = (x+2). 3 (x+2)+2 (x-2) = 20. x=18/5. time = distance / rate. time = 20 / ( (18/5)-2) time = 12.5 hours. However the answer says that this is wrong and it's because (3x+6)+ (2x-4) = 20 should've been (3x+6)- (2x-4…

SOLVED:Rowing with the current, a canoeist paddled 14 ...

    https://www.numerade.com/questions/rowing-with-the-current-a-canoeist-paddled-14-mathrmmi-in-2-mathrmh-rowing-against-the-current-the-c/
    Rowing with the current, a canoeist paddled $14 \mathrm{mi}$ in $2 \mathrm{h}$. Rowing against the current, the canoeist could paddle only $10 \mathrm{mi}$ in the same amount of time. Find the rate of the canoeist in calm water and the rate of the current.

Can One Person Paddle a Two Person Canoe? (Facts to Know ...

    https://hydropursuit.com/can-one-person-paddle-a-two-person-canoe-facts-to-know/
    One person can paddle a two-person canoe if they deliberately seat themselves toward the canoe’s center of gravity and employ corrective paddling strokes to keep the canoe on a straight path. With that being said, solo canoes are still better suited for solo paddling.

How Far does an average canoeist travel in an average day ...

    https://www.songofthepaddle.co.uk/how-far-does-an-average-canoeist-travel-in-an-aver-t31700.html
    Aug 18, 2011 · The paddling "day" might be as short as 4 hours of actually moving the canoe at a reasonable cruising pace: familiar to me from my club-paddling days, and from recent trips with others, but resulting in a diabolical "average" pace!

Final Forty Key - SharpSchool

    http://p1cdn1static.sharpschool.com/UserFiles/Servers/Server_10640393/File/final_forty_key.pdf
    5. A canoeist paddled for 4 hours with a 6-km/hr current to reach a campsite. The return trip against the same current took 10 hours. Find the speed of the canoe in still water. 6. To deliver a package, a courier must travel at a speed of 60 milhr by car and then use a ferry whose speed is 20 milhr in still water. The courier drives the car

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